WebMar 1, 2016 · 1) divide it by 2 2) take the result of 1) and square it. 3) add the result of 2) and add it to both sides of the equation. So the coefficient of x is -8 -8/2 = -4 (-4) 2 = 16 x 2 -8x = 0 x 2 -8x + 16 = 0 + 16 x 2 -8x+16 = 16 If we factor the left side, we have (x-4) (x-4) = 16 Which is equivalent to (x-4) 2 = 16 and (x-4) 2 = 4 2 WebJun 17, 2024 · Solution 2 Complete the square to find that $$ (x-4)^2+1>0 $$ for all real $x$. Solution 3 Since the discriminant is negative, $x^2-8x+17$ is never $0$. And it is …
Show that $x^2-8x+17>0$ for all real values of x
WebSOLUTION: x^2-8x+17=0 Solvers Lessons Click here to see ALL problems on Polynomials-and-rational-expressions Question 185939: x^2-8x+17=0 Answer by jim_thompson5910 (35256) ( Show Source ): You can put this solution on YOUR website! Start with the given equation. Notice we have a quadratic equation in the form of where , , and WebOct 31, 2024 · 7 views 1 month ago In this video, we learn how to show that x^2 -8x + 17 is greater than 0? This is a typical question come in exam. EXPONENTIAL AND LOGATHMIC … film effect headlights
Solve 2x^2+8x-17=0 Microsoft Math Solver
WebMay 18, 2016 · x2 +8x + 16 = 0. The equation is of the form ax2 + bx + c = 0 where: a = 1,b = 8,c = 16. The Discriminant is given by: Δ = b2 − 4 ⋅ a ⋅ c. = (8)2 − (4 ⋅ 1 ⋅ 16) = 64 −64 = 0. The solutions are found using the formula. x = −b ± √Δ 2 ⋅ a. WebShow that x^2 - 8x +17 <0 for all real values of x consider the discriminant b 2 -4ac 8 2 -4x1x17 64-68=-4 discriminant is below 0, there are no real roots therefore x 2 - 8x +17 <0 … Webx 2 + 8x + 17 = 0 has two solutions: x = -4 + √ 1 • i or x = -4 - √ 1 • i . Solve Quadratic Equation using the Quadratic Formula 2.3 Solving x 2 +8x+17 = 0 by the Quadratic Formula . … group game for middle schoolers