WebSolution Verified by Toppr Correct option is A) When nitrobenzene is reduced with a metal and acid (Sn/HCl, Zn/HCl etc.), aniline is obtained. The intermediate products nitrosobenzene and phenylhydroxylamine are never isolated because these are reduced more rapidly than nitrobenzene. Was this answer helpful? 0 0 Similar questions WebQuestion: identify the product of the following reactions a. 1,3-dimethyl-2-nitrobenzene with 1. SnCl2 and HCl 2. NaOH b. product of a with ClCH2COCl c. product of b with …

Efficient reductions of nitroarenes with SnCl2 in ionic liquid

WebYour electron configurations match tin and not zinc. Then your mechanism is good. $\ce{SnCl2}$ is a reducing agent and could do this reaction. $\ce{SnCl2}$ is not stannic chloride, but stannous chloride. Stannic chloride is $\ce{SnCl4}$. Regardless $\ce{SnCl2}$ would work. $\ce{ZnCl2}$ would not work. Web3 de jul. de 2024 · When aniline is react with sodium nitrate NaNO2 and ( hydrochloric acid) HCl at 0 – 5°C then, it give benzene diazonium Chloride (Diazonium salt) as a product. benzene diazonium Chloride prepared from aniline After reaction you can see First N2 is removed and sodium chloride (Nacl) is removed. fred perry twin tipped t shirt burgundy

Tin(ii) chloride dihydrate/choline chloride deep eutectic solvent ...

WebNitrobenzene when reacted with tin and hydrochloric acid, i.e., in acidic medium, the product formed is: WebShen et al. have achieved a Friedel-Crafts alkylation of the normally unreactive nitrobenzene (Equation (37)) < 90JOC3961 >. AlCl 3 coordinates the nitro group and further deactivates the benzene ring. Sulfuric acid does not do this and so the reaction proceeds in moderate yield. The ortho: meta: para ratio is 19. : 70 : 11.. The selectivity of this Friedel-Crafts … http://www.yearbook2024.psg.fr/ua1Sc2G_sncl2-reduction-mechanism.pdf blink fitness 116th street